If p = .9, what is the frequency of the heterozygote? .81+(2)(.9)(.1) + (.01) .10 .81 + .18 .18

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02-10-2017
Mathematics

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If p = .9, what is the frequency of the heterozygote? .81+(2)(.9)(.1) + (.01) .10 .81 + .18 .18

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What value of x makes the equation true ? 4(2x-4)=16

mathmate mathmate · Answer 1 · 2017-10-02T15:42:20+02:00

mathmate mathmate

02-10-2017

Write down the Punnett square to find the frequencies:

R(.9) r(.1)
R 0.81 0.09
r 0.09 0.01

The answer choices given are confusing. I'll let you figure out the choices.

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